2[3-2(z+4)]=3(4-2)

Solution for 2[3-2(z+4)]=3(4-2) equation:

Simplifying
2[3 + -2(z + 4)] = 3(4 + -2)

Reorder the terms:
2[3 + -2(4 + z)] = 3(4 + -2)
2[3 + (4 * -2 + z * -2)] = 3(4 + -2)
2[3 + (-8 + -2z)] = 3(4 + -2)

Combine like terms: 3 + -8 = -5
2[-5 + -2z] = 3(4 + -2)
[-5 * 2 + -2z * 2] = 3(4 + -2)
[-10 + -4z] = 3(4 + -2)

Combine like terms: 4 + -2 = 2
-10 + -4z = 3(2)

Multiply 3 * 2
-10 + -4z = 6

Solving
-10 + -4z = 6

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -4z = 6 + 10

Combine like terms: -10 + 10 = 0
0 + -4z = 6 + 10
-4z = 6 + 10

Combine like terms: 6 + 10 = 16
-4z = 16

Divide each side by '-4'.
z = -4

Simplifying
z = -4